Answer:
29 is answer.
Step-by-step explanation:
Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.
To find average velocity of the object over the interval of time [1,3]
We know that derivative of s is velocity and antiderivative of velocity is position vector .
Since moving along a line equation of s is
use two point formula
gives the position at time t.
Average velocity in interval (1,3)
=![\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3-1%7D%20%28s%283%29-s%281%29%29%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20%5B87%2B58-29-58%5D%5C%5C%3D29)
6a+8b; when a variable is next to a coefficient then that means they are multiplying each other, we just don't know what a or b is.
Answer:
1. y = -125000x + 700000
2. Negative
3. Positive
Step-by-step explanation:
1. The no. Of gallons before irrigation
= 700000
After irrigation = 200000
This means that there was a reduction of 500000 gallons in 4 hours which indicates that 125000 gallons were used (on an average) in 1 hour
So the equation is
y = 700000 - 125000x
Hope this helps
Can u plz mark me as brainliest?
My rank needs to increase so plz
This is the answer. Always remember SOH CAH TOA
Had fun solving this ngl
