<h2><u>EQUATION</u></h2><h3>Exercise</h3>
2(3 + 3y) + y = 11
First, apply the distributive property:
2(3 + 3y) + y = 11
6 + 6y + y = 11
6 + 7y = 11
Substract 6 from both sides:
6 - 6 + 7y = 11 - 6
7y = 5
Divide both sides by 7:


<h3><u>Answer</u>. The value of y = 5/7.</h3>
Answer:
12.35 should be the 10th term sorry if im wrong tho
Step-by-step explanation:
Answer:
vzosbakabaoabka a
Step-by-step explanation:
ukiukiukiyji
Get one x+y=3 to y=x+3 and plug it into x-y=1 and you get x-(x+3)=1. Destitute the x and solve. Once you get what x equals plug it to to either equation for the value of x and solve for y
Given:
The given sequence is:

To find:
The recursive formula for
, the nth term of the sequence.
Solution:
We have,

Here, the first term is 5.



The common difference is -7.
The recursive formula for the nth term of the sequence is

Where,
is the common difference.
Putting
in the above formula, we get


Therefore, the recursive formula for the nth term of the sequence is
.