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2 years ago

5

First person to give answer with work will get brainliest!!

1 answer:

Ket [755]2 years ago

4 0

All you will have to do is put this inside of a graph and then see if it goes through the origin.

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12 pls. Dis is due tomorrow I need helppp

givi [52]

Multiplying positive numbers always comes out positive, no matter how many there are. So you can forget about the positive ones.

Every two negative numbers in a multiplication produce a positive.
Another way to say that is: If the number of negative ones is EVEN,
the answer is positive, and if it's ODD, the answer is negative.

That monster product of eight numbers in problem #12 will be negative,
because there are an odd amount of negative factors in it.

7 0

2 years ago

Solve for a. a+(−4)=−13

dangina [55]

In your equation: a+(-4)=-13
you then add four to each side,
so a= negative 13 plus 4
so a= -9

6 0

2 years ago

Read 2 more answers

What is the value of the fourth power of 10

Shalnov [3]

$10^4 = 10\times 10 \times 10 \times 10 = 100 \times 10 \times 10 = 100 \times 100 = \boxed{10,000}$

3 0

2 years ago

Read 2 more answers

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

as

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

2 years ago

14 plus 5(x plus 3) minus 7

Damm [24]

14+5(x+3)-7
14+(5x+15)-7
7+5x+15
5x+22

7 0

2 years ago