Answer:
length of rectangle=16 inches
width of rectangle=10.5 inches
Step-by-step explanation:
given ,perimeter of rectangle=53 inches
let ,length of rectangle= l=2b-5
width of rectangle=b
p=2(l+b)
53=2(2b-5+b)
26.5=3b-5
31.5=3b
b=
b=10.5 inches
l=21-5=16 inches
Answer:
D) 40
Step-by-step explanation:
First, identify what you know:
1) Michael is directed to pick a number between 1 and 50
2) Michael picks a number that is less than 50
3) The number chosen, is a multiple of 5 and 8
A multiple is a number that can be divided by another number without a remainder. What number can be divided by 5 and 8 without having a remainder?
40/5 = 8
40/8 = 5
Michael chose 40!!
Hey there!
Let's make one and solve it.
Fraction division is solved by using a simple rule:
"keep, switch, flip!"
So if we have:
4/8 divided by 5/9
We keep the 4/8, switch the division to multiplication, and flip the 5/9 to 9/5:
4/8 * 9/5 = 36/40 = 18/20 = 9/10
Hope this helps!
Answer:
Present Value = ![X [\frac{1}{(1 + 0.12)^{1} } + \frac{1}{(1 + 0.12)^{2} } + \frac{1}{(1 + 0.12)^{3} } + \frac{1}{(1 + 0.12)^{4} } + \frac{1}{(1 + 0.12)^{5} } ]](https://tex.z-dn.net/?f=X%20%5B%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B1%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B2%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B3%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B4%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B5%7D%20%7D%20%5D)
Step-by-step explanation:
To find - If discount rate is 12%, the present value of Rs X received at the end of each year for the next five years is equal to .... ?
Solution -
We know that, formula for finding the Present vale is given by
Present value = Future value / (1 + r)ⁿ
where r is the rate of interest
and n is Number of periods
Now,
Here in the question, we have
r = 12% = 12/100 = 0.12
n = 5
Also, Given that, we have received Rs X at the end of each year
So,
Present Value = 
= ![X [\frac{1}{(1 + 0.12)^{1} } + \frac{1}{(1 + 0.12)^{2} } + \frac{1}{(1 + 0.12)^{3} } + \frac{1}{(1 + 0.12)^{4} } + \frac{1}{(1 + 0.12)^{5} } ]](https://tex.z-dn.net/?f=X%20%5B%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B1%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B2%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B3%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B4%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B5%7D%20%7D%20%5D)
⇒Present Value = ![X [\frac{1}{(1 + 0.12)^{1} } + \frac{1}{(1 + 0.12)^{2} } + \frac{1}{(1 + 0.12)^{3} } + \frac{1}{(1 + 0.12)^{4} } + \frac{1}{(1 + 0.12)^{5} } ]](https://tex.z-dn.net/?f=X%20%5B%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B1%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B2%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B3%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B4%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B5%7D%20%7D%20%5D)
Answer:
1st one, I think so. I'm pretty positive