Answer:
The diameter of the base of the cylinder is 2 cm.
Step-by-step explanation:
<u>GIVEN</u> :
As per given question we have provided that :
- ➣ Height of cylinder = 14 cm
- ➣ Curved surface area = 88 cm²

<u>TO</u><u> </u><u>FIND</u> :
in the provided question we need to find :
- ➠ Radius of cylinder
- ➠ Diameter of cylinder

<u>USING</u><u> </u><u>FORMULAS</u> :


- ➛ Csa = Curved surface area
- ➛ π = 22/7
- ➛ r = radius
- ➛ h = height
- ➛ d = diameter

<u>SOLUTION</u> :
Firstly, finding the radius of cylinder by substituting the values in the formula :

Hence, the radius of cylinder is 1 cm.
———————————————————————
Now, finding the diameter of cylinder by substituting the values in the formula :

Hence, the diameter of the base of the cylinder is 2 cm.

Answer:
.
Step-by-step explanation:
A point of the form
belongs to the graph of this function,
, if and only if the equation of this function holds after substituting in
and
.
The question states that the point
belongs to the graph of this function. Thus, the equation of this function,
, should hold after substituting in
and
:
.
.
Solve this equation for the constant
:
.
Thus,
.
Answer:
<h2> 6/35</h2>
Step-by-step explanation:
This problem is on fraction
given data
chocolate chip cookies= 12
lemon cookies = 6
strawberry cookies= 17
the total cookies is = 12+6+17
=35 cookies
Therefore the fraction that indicates the lemon cookies is
=the number of lemon cookies/total cookies
=6/35
Hence the fraction lemon is 6/35
Answer: 890.12 cm^3
Step-by-step explanation:
The formula for the volume of a cylinder is

V=628.3185307 cm^3
or simply
V=628.32 cm^3
Since, you know the radius of the hemisphere on top, you also know the radius since the height of the hemisphere is the same as it is wide.
Next, the formula for the volume of a sphere is

so the volume of a hemisphere is half of that or:

V= 261.7993878 cm^3
or simply
V=261.80 cm^3
Finally, you add both of the volumes together to get
V= 890.1179185 cm^3
or simply
V=890.12 cm^3
Answer:
Step-by-step explanation:
47 and half .................