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Alla [95]
3 years ago
9

At 39 weeks gestation, a 26 year-old woman is admitted for precipitous labor and vaginally delivers a healthy baby girl. what ic

d-10-cm codes are reported on the maternal record
Biology
1 answer:
BaLLatris [955]3 years ago
3 0

The answer is Z3A.39


ICD-10-CM code are used to express diagnosis of the a patient. The code Z3 is used for patient with diagnosis related to reproduction. The term Z3A.XX is used for pregnancy where "XX" is the number of weeks of gestation. Because the woman is at 39 weeks, then the code would be Z3A.39

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Answer: 1/16, or approximately 6.25% (see explanation below)

Explanation:

Answering this question requires two steps.

First, we need to figure out the probability that this couple will have a child with albinism in the first place. We know the following:

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Let ( M = normal gene ) and ( m = mutated gene ). Since the condition is recessive, the affected child can be assumed to have a “mm” genotype. Barring the possibility of a de novo mutation (which are assumed to be rare), the affected child must have inherited one ”m” allele from each parent. Since both of them are unaffected, however, we can assume that they are both carriers (genotype “Mm”). In conclusion, 1/4 of their offspring (25%) <em>for any given pregnancy</em> may be expected to have albinism. See the resulting Punnett square:

<u>       |      M    |      m   </u>

<u>M    |    MM   |    Mm  </u>

<u>m    |    Mm   |    mm  </u>

Note that the question asks about the probability that not one but two consecutive births result in affected children. Since it can be assumed that both events are independent (meaning: the outcome of a pregnancy does not influence the outcome of following ones), we may apply the rule of multiplication for probabilities. The final answer is therefore 1/4 * 1/4 = 1/16.

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