I believe that the answer is A, if I am not mistaken!
The scenario will be Son: 25% colorblind daughter: 25% colorblind son: 25% of carrier daughters with normal vision: 25% normal son
<h3>What is color blindness?</h3>
The condition is frequently inherited. Certain eye diseases and medications are also possible causes. Men are more affected than women.
Color blindness is characterized by the inability to distinguish between red and green shades.
A colorblind man's genotype is XcY, and a heterozygous carrier female's genotype is XcX. A cross between XcY and XcX would result in progeny with the following ratio=
Son: 25% colorblind daughter: 25% colorblind son: 25% of carrier daughters with normal vision: 25% normal son.
Thus, the couple is likely to have a son who is half normal and half affected. Similarly, the couple is likely to have 50% normal daughters and 50% colorblind daughters.
For more details regarding color blindness, visit:
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Cation-exchange chromatography is used when the molecule of interest is positively charged, the stationary phase is negatively charged and positively charged molecules are loaded to be attracted to it. So, the amino acids with negative charge will elute the first. Glutamate, leucin, arginine is the order of elution because of their pI values ~3, ~6 ~10.
