Can y’all answer my recent question and i’ll answer this plz
1.30 :)
All you have to do is see if the number on your left is greater than 5 or not if it’s is round up 1 if not it stays the same !
Hope this helped !!!
Answer:
Step-by-step explanation:
Total number of laptops, N = 20
Defective laptops, n = 3
School purchase 2 laptops
Case 1:
Both laptops are non defective
Probability to choose 2 laptops which are non defective
Number of non defective laptops = 20 - 3 = 17
Total number of laptops = 20
Probability, P = 17/20 = 0.85
Case 2:
One laptop is defective
Probability to chose 1 defective and one non defective laptop
P' = 3/20 x 17/19 = 0.134
Case 3:
Both laptops are defective
Choosing of 2 laptops out of 3 = 3 C 2 = 3
choosing of 2 laptops out of 20 = 20 C 2 = 190
Probability of choosing two defective laptops = 3 / 190 = 0.0158
P'' =
Answer:
see below
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos ? = adj / hyp
cos ? = 30/48
Taking the inverse cos of each side
cos ^ -1 cos ? = cos ^ -1 ( 30/48)
? = 51.31781255
To the nearest degree
? = 51
Since this is a right triangle, we can use trig functions
cos ? = adj / hyp
cos ? = 40/53
Taking the inverse cos of each side
cos ^ -1 cos ? = cos ^ -1 ( 40/53)
? = 40.99935365
To the nearest degree
? = 41
Since this is a right triangle, we can use trig functions
tan ? = opp/adj
tan ? = 1/2
Taking the inverse tan of each side
tan ^ -1 tan ? = tan ^ -1 ( 1/2)
? = 26.56505118
To the nearest degree
? = 27
Since this is a right triangle, we can use trig functions
sin ? = opp / hyp
sin ? = 29/35
Taking the inverse sin of each side
sin ^ -1 sin ? = sin ^ -1 ( 29/35)
? = 55.95226763
To the nearest degree
? = 56