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aleksklad [387]
3 years ago
14

Give an example of two 2×2 matrices A and B, neither of which is the zero matrix or the identity matrix, such that AB=BA.

Mathematics
1 answer:
Katena32 [7]3 years ago
6 0

Let

A=B=\begin{bmatrix}0&1\\1&0\end{bmatrix}

Then

AB=BA=\begin{bmatrix}0&1\\1&0\end{bmatrix}^2=\begin{bmatrix}1&0\\0&1\end{bmatrix}

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Use the distributive property to match equivalent expressions.
NeTakaya

Answer:

<h3>By using the distributive property the matched equivalent expressions are</h3><h3>1) -7(-4+x) =28-7x </h3><h3>2) -7(4-x) =-28+7x </h3><h3>3) 7(4+x) =28+7x </h3><h3>4) 7(-4-x) =-28-7x </h3>

Step-by-step explanation:

Given that by using the distributive property to match the given equivalent expressions.

1) Given expression is -7(-4+x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

-7(-4+x) =(-7)(-4)+(-7)(x)

=28-7x

<h3>∴ -7(-4+x) =28-7x </h3>

2) Given expression is -7(4-x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

-7(4-x) =(-7)(4)+(-7)(-x)

=-28+7x

<h3>∴ -7(4-x) =-28+7x </h3>

3) Given expression is 7(4+x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

7(4+x) =(7)(4)+(7)(x)

=28+7x

<h3>∴ 7(4+x) =28+7x </h3>

4) Given expression is 7(-4-x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

7(-4-x) =(7)(-4)+(7)(-x)

=-28-7x

<h3>∴ 7(-4-x) =-28-7x </h3>

Hence the matched equivalent expressions are

1) -7(-4+x) =28-7x

2) -7(4-x) =-28+7x

3) 7(4+x) =28+7x

4) 7(-4-x) =-28-7x

4 0
3 years ago
Reyna has 3 dimes (worth 10 these coins at random, what is the probability that the two coins together least 35 cents? cents eac
larisa86 [58]

Answer:

IDK

Step-by-step explanation:


3 0
3 years ago
Why is it important to know the categories of numbers?
leonid [27]
Its important to know the categories of number because its in math
6 0
3 years ago
Naomi has earned $51 mowing lawns the past two days. She worked 1 1/2 hours yesterday and 2 3/4 hours today. If Naomi is paid th
stiks02 [169]

12 Dollars An Hour

51/4.25= 12

4 0
4 years ago
PLEAS HELP...FIRST CORRECT ANSWER WILL GET BRAINLIEST....PLEASE ANSWER NOW!!!!
dexar [7]

*a clearer picture containing the graph is shown in the attachment

Answer:

20% of the class earned a D

Step-by-step Explanation:

Step 1: Determine the total number of students represented on the graph:

9 students => D

5 students => C

14 students => B

17 students => A

Total number of students = 45

Step 2: Express each category of students who scored a particular grade as a fraction and as percentage.

9 students => D => \frac{9}{45} = \frac{1}{5} => as percentage, we have \frac{1}{5} * 100 = 20 percent

5 students => C => \frac{5}{45} = \frac{1}{9} => as percentage, we have \frac{1}{9} * 100 = 11.1 percent

14 students => B => \frac{14}{45} => as percentage, we have \frac{14}{45} * 100 = 31.1 percent

17 students => A => \frac{17}{45} => as percentage, we have \frac{17}{45} * 100 = 37.8 percent

Step 3: Check each statement to see if they are true or not based on the calculations above.

Statement 1: "⅕ of the students earned a C."

This is NOT TRUE From our calculation, ⅑ of the students earned a C.

Statement 2: "3% more students earned an A than a B." This is also NOT TRUE.

37.8% earned A, while 31.1% earned a B. Thus, about 6.7% more students earned an A than a B.

Statement 3: "20% of the class earned a D".  This is TRUE.

Check calculation in step 2.

Statement 4: "¼ of the class earned a B". This is NOT TRUE.

¼ is 25% of the class. Those who earned a B account for 31.1% not 25% (¼ of the class).

The correct statement is: "20% of the class earned a D"

7 0
3 years ago
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