Answer:
the minimum is (1,-9)
Step-by-step explanation:
y = 5x^2 - 10x - 4
since the parabola opens upward 5>0, this will have a minimum
it will occur along the axis of symmetry h=-b/2a
y =ax^2 +bx+c
h = -(-10)/2*5
h = 10/10 =1
the minimum occurs at x =1
the y value for the minimum is calculated by substituting x =1 back into the equation
y = 5 * 1^2 - 10*1 -4
y = 5*1^2 -10 -4
y = 5-10-4
y = -9
the minimum is (1,-9)
If we know that two sets of corresponding angles and the corresponding included sides are congruent in two triangles, what can we say about the triangles?
Answer:
Step-by-step explanation:
We have the equations
4x + 3y = 18 where x = the side of the square and y = the side of the triangle
For the areas:
A = x^2 + √3y/2* y/2
A = x^2 + √3y^2/4
From the first equation x = (18 - 3y)/4
So substituting in the area equation:
A = [ (18 - 3y)/4]^2 + √3y^2/4
A = (18 - 3y)^2 / 16 + √3y^2/4
Now for maximum / minimum area the derivative = 0 so we have
A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0
-3/8 (18 - 3y) + √3 y /2 = 0
-27/4 + 9y/8 + √3y /2 = 0
-54 + 9y + 4√3y = 0
y = 54 / 15.93
= 3.39 metres
So x = (18-3(3.39) / 4 = 1.96.
This is a minimum value for x.
So the total length of wire the square for minimum total area is 4 * 1.96
= 7.84 m
There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.
Answer:
Zeros: x
=
1
,
−
2
,
2 End Behavior: Falls to the left and rises to the right.
Y-intercept: (0,4)
Step-by-step explanation:
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