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2 years ago

I need help with solving please! thank you!

Mathematics

2 answers:

Brilliant_brown [7]2 years ago

8 0

I also think it’s c(5,3) I’m not sure but someone else said it too so it just may be right

agasfer [191]2 years ago

7 0

Answer:

C (5,3)

Step-by-step explanation:

I hope it is correct because I don't know if it is hope you also have a good day and pass this test

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What is 4/15 / -3.4<br>

seraphim [82]

Answer:

Factor the numerator and denominator and cancel the common facotors which would give you 0.07843137

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3 years ago

It takes 3men 5 hours to repair a road.how long will it take 5 men to do the job if they work at the same rate

Ksju [112]

Answer:

3 hours

Step-by-step explanation:

3 Men-5 hours

5 men-?

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3 years ago

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A school bus has seating for 75 students. There are 13 buses at a school. What is the maximum number of students

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Answer:

75 students and 13 buses are just 75 x 13

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Step-by-step explanation:

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2 years ago

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Please help it’s due in an hour

dolphi86 [110]

I think that the answer is C

3 0

2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago