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Lina20 [59]
4 years ago
9

Is the system of equations is consistent, consistent and coincident, or inconsistent? y=−x−13y=−3x+2

Mathematics
2 answers:
Klio2033 [76]4 years ago
6 0
Its inconsistent .......

UkoKoshka [18]4 years ago
4 0

Answer:

The System of Equation is Consistent.

Step-by-step explanation:

Given: System of equations y = -x - 13 and y = -3x + 2

To find: System of equation is consistent or inconsistent

System of equation is consistent if it has a unique solution or infinitely many solution and it is in consistent if it has no solution.

So we check if given system of equation has unique solution or infinitely many solution or no solution by checking their ratio.

Rewrite the system of equation,

x + y +13 = 0 and 3x + y - 2 = 0

a_1=1\:,\:b_1=1\:,\:c_1=13\:and\:a_2=3\:,\:b_2=1\:,\:c_2=-2

Now,

\frac{a_1}{a_2}=\frac{1}{3}

\frac{b_1}{b_2}=\frac{1}{1}

\frac{c_1}{c_2}=\frac{13}{-2}

Since, \frac{a_1}{a_2}\neq\frac{b_1}{b_2}

Thus, System of equation has unique solution.

Therefore, The System of Equation is Consistent.

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Answer:

f(x)=237x/421x-515

Step-by-step explanation:

6 0
4 years ago
Find the area of the circle. Round your answer to the nearest hundredth 3in
FrozenT [24]

Answer:

28.26 square inches

Step-by-step explanation:

Formula for area of a circle:

A=\pi r^2

Radius is 3.

A= \pi (3)^2\\A=\pi 9

Use 3.14 for pi:

A = 3.14 * 9 = 28.26\\A=28.26

The area should be 28.26 square inches.

4 0
3 years ago
A tissue can be 0.000075 meters thick.
Setler [38]

Answer:

The required expression is 7.5\times 10^5

Step-by-step explanation:

Consider the provided information.

A tissue can be 0.000075 meters thick and we need to represent it into scientific notation.

Steps to write a number in scientific notation.

  • Move the decimal place to the right so that the new number from 1 up to 10.
  • Determine the exponent, the exponent is the number of times you moved the decimal.

Now, consider the number 0.000075

Move the decimal point to 5 place right so that the new number from 1 up to 10.

Now, put the exponent the number of times you moved decimal. 7.5\times 10^5

Hence, the required expression is 7.5\times 10^5

5 0
4 years ago
Given: F(x) = x + 2 and G(x) = 3x + 5<br><br> (F * G) (x) =
RUDIKE [14]

Answer:

3x²+11x+20

Step-by-step explanation:

x(3x+5)+2(3x+5)

3x²+5x+6x+20

3x²+11x+20

8 0
3 years ago
Please answer this for me
coldgirl [10]

In 1-4, to determine whether a sequence is either arithmetic or geometric, you need to look at differences of consecutive terms (arithmetic) and ratios of consecutive terms (geometric). If you can't find it, the sequence will fall under the "neither" category.

For example, the differences between consecutive terms in the first sequence are

\left\{2-4,\dfrac12-2,\dfrac14-\dfrac12,\ldots\right\}=\left\{-2,-\dfrac32,-\dfrac14,\ldots\right\}

If the sequence was arithmetic, the difference between consecutive terms would have been the same constant throughout this list. But that's not the case, so this sequence is not arithmetic.

The ratios between consecutive terms are

\left\{\dfrac24,\dfrac{\frac12}2,\dfrac{\frac14}{\frac12},\ldots\right\}=\left\{\dfrac12,\dfrac14,\dfrac12,\ldots\right\}

The sequence would have been geometric if the list contained the same value throughout, but it doesn't. So this sequence is neither arithmetic nor geometric.

Meanwhile, in the second sequence, the differences are

\{-1-(-6),4-(-1),9-4,\ldots\}=\{5,5,5,\ldots\}

so this sequence is arithmetic.

In 5-6, you know the sequences are arithmetic, so you know that they follow the recursive rule

a_n=a_{n-1}+d

For example, in the fifth sequence we know the first term is a_1=4. The common difference between terms is d=9-4=5. So using the rule above, we have the pattern

a_2=a_1+d

a_3=a_2+d=a_1+d(2)

a_4=a_3+d=a_1+d(3)

and so on, so that the n-th term is determined entirely by a_1 with the formula

a_n=a_1+d(n-1)

This means the 21st term in the fifth sequence is

a_{21}=a_1+5(21-1)=4+5(20)=104

The process is simple: identify a_1 and d, plug them into the formula above, then evaluate it at whatever n you need to use.

8 0
3 years ago
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