Question

Let f(x)=201+9e3x . What is the y-intercept of the graph of f(x) ?

Answer 1

Answer:

The y-intercept is (0,210)

Step-by-step explanation:

We have the function, $f(x)=201+9e^{3x}$

So, we know that,

'y-intercept is the point on the graph where the function crosses y-axis'.

i.e. y-intercept is obtained when x=0.

Thus, substituting x=0 in the given function, we get,

$f(0)=201+9e^{3\times 0}$

i.e. $f(0)=201+9e^{0}$

i.e. $f(0)=201+9\times 1$

i.e. $f(0)=201+9$

i.e. f(0) = 210

Also, we can see from the given graph that the function crosses y-axis at (0,210).

Hence, the y-intercept is (0,210).

Answer 2

The y-intercept happens when x=0. So, F(0) = 201+9e^3(0). 3*0=0 and e^0=1. So you have f(0) = 201+9, f(0) = 210