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3 years ago

2.5 more than the quotient of h and 3 is w

1 answer:

5 0

4
$\beta x^{2} }1&2&3\\4&5&6\\7&8&9\end{array}\right] x_{123} \lim_{n \to \infty} a_n \sqrt{x} \sqrt[n]{x} x_{123} \neq \pi$

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3m + 4m = 42<br><br> Please help.<br><br> I think the answer is either 7 or -42

Katyanochek1 [597]

7m=42 thus m=6
Because 42/7=6

7 0

3 years ago

Read 2 more answers

A winter coat was originally $65 and is now marked up by 2% . What is the price after the markup?

ratelena [41]

It would be 66.3 because 2% Coverts to .02 then you multiply that to 65 and get 1.3 and then you add that to 65

5 0

3 years ago

Lara is putting lace trim around the border of a circular tablecloth. The tablecloth has a diameter of 1.2 meters. What is the l

mylen [45]

Answer:

3.8m

Step-by-step explanation:

Since Lara is putting lace trim around the border of a circular tablecloth, by the time she finishes she has covered the circumference.

The circumference of a circle is calculated using:

$C=\pi \: d$

where d is the diameter of the circle.

It was given that the diameter of the circular table cloth is 1.2 meters.

$C=3.14 \times 1.2$

$C=3.768$

Therefore the length of the lace she needed is 3.8m

6 0

3 years ago

How do you convert between fractions, decimals, and percentages?

svlad2 [7]

To convert to percent from fraction you divide the numerator by the denominator. from percent to decimal you move two decimal places to the left.

5 0

3 years ago

Read 2 more answers

What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

LenKa [72]

${\bold{\red{\huge{\mathbb{QUESTION}}}}}$

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

$\bold{ \red{\star{\blue{GIVEN }}}}$

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

$\bold{\blue{\star{\red{TO \: \: FIND}}}}$

Average cost of 7 articles

$\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}$

$\red{AVERAGE = \frac{TOTAL \: COST}{ NUMBER \: OF\: ARTICLES }}$

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

$Average \: cost \: of \: 7 \: articles - > \\ \frac{(3 \times 30k) + (12 .5k \times 4)}{7} \\ \frac{90k + 50k}{7} \\ \frac{140k}{7} \\ \blue {Average \: cost \: of \: 7 \: articles - >} \\ 20k$

5 0

3 years ago