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Vera_Pavlovna [14]
3 years ago
15

Find the slope of the line through each pair of points

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0

Answer:

12/19

Step-by-step explanation:

We can find the slope given the two points by using the following formula

m = (y2-y1)/(x2-x1)

   = (-3 - -15)/(3 -  -16)

   = (-3 +15)/(3+16)

   12/19

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Plz help wit dis<br> its due today
julia-pushkina [17]

1. Sry, I am confused by this one

2. Positive Integer factors of 196 = 2, 4, 7, 28, 196/2, 2, 7, 7, leaves it with no remainder.

3. Neither

4. Prime

5. Composite

6. 80, 96, 112 (pattern: add 16 each time)

7. 29, 36, 38 (pattern: add 7, add 2 and so on)

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8 0
3 years ago
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Factor -22 out of 15.4b -6.6
valina [46]

Answer:

-7b+3

Step-by-step explanation:

first step you will find numbers if you take -2.2 to get those numbers

7 0
2 years ago
Examine the following expression.
svetoff [14.1K]

Answer:

True expressions:

  • The constants, -3 and -8, are like terms.  
  • The terms 3 p and p are like terms.  
  • The terms in the expression are p squared, negative 3, 3 p, negative 8, p, p cubed.
  • The expression contains six terms.
  • Like terms have the same variables raised to the same powers.

Step-by-step explanation:

The expression is:

p² - 3 + 3p - 8 + p + p³

False expressions:

  • The terms p squared, 3 p, p, and p cubed have variables, so they are like terms.  (They don't have the same exponents)
  • The terms p squared and p cubed are like terms.    (They don't have the same exponents)
  • The expression contains seven terms. (It contains 6 terms)
6 0
3 years ago
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Verify sin^4 x - sin^2 x = cos^4 x - cos^2 x is an identity
Citrus2011 [14]

Answer:

(identity has been verified)

Step-by-step explanation:

Verify the following identity:

sin(x)^4 - sin(x)^2 = cos(x)^4 - cos(x)^2

sin(x)^2 = 1 - cos(x)^2:

sin(x)^4 - 1 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2

-(1 - cos(x)^2) = cos(x)^2 - 1:

cos(x)^2 - 1 + sin(x)^4 = ^?cos(x)^4 - cos(x)^2

sin(x)^4 = (sin(x)^2)^2 = (1 - cos(x)^2)^2:

-1 + cos(x)^2 + (1 - cos(x)^2)^2 = ^?cos(x)^4 - cos(x)^2

(1 - cos(x)^2)^2 = 1 - 2 cos(x)^2 + cos(x)^4:

-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = ^?cos(x)^4 - cos(x)^2

-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = cos(x)^4 - cos(x)^2:

cos(x)^4 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2

The left hand side and right hand side are identical:

Answer:  (identity has been verified)

3 0
3 years ago
Given the geometric sequence where a1=1 and the common ratio is 6, what is the domain for n?​
kari74 [83]

We have been given that a geometric sequence's 1st term is equal to 1 and the common ratio is 6. We are asked to find the domain for n.

We know that a geometric sequence is in form a_n=a_1(r)^{n-1}, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

r = Common ratio,

n = Number of terms in a sequence.

Upon substituting our given values in geometric sequence formula, we will get:

a_n=1\cdot (7)^{n-1}

Our sequence is defined for all integers such that n is greater than or equal to 1.

Therefore, domain for n is all integers, where n\geq 1.

4 0
3 years ago
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