Solve the equation 19 − x = 27 x = 8 x = 18 x = 46 x = -8

A rectangular garden has a perimeter of 36 yards and a width of 8 yards.

xeze [42]

Answer:

80 square yards

Step-by-step explanation:

We know we have a width of 8 yards and a perimeter of 36.

how I figured it out was:

36=(8*2) * (x*2)

8*2=16

36-16=10

So now we know the length and width.

area of a rectangle is lw (length * width)

10*8=80.

8 0

3 years ago

Can someone PLEASE help me with this

Mekhanik [1.2K]

Answer:

4.5 u

Step-by-step explanation:

There are many ways to do it, the most easier is this:

Area=(b*h)/2

Area of ABD = (3*3)/2 = 4.5 u

3 0

3 years ago

Read 2 more answers

Please help me with this homework

soldi70 [24.7K]

Step-by-step explanation:

we see f(x), which is |x|.

and we see g(x), which is clearly the same basic graph, it is just shifted 3 units down in y direction.

shifts are simply done by keeping the original function definition and then add it subtract a certain constant that then adapts every original functional value.

so, a shift down by 3 units is done by adding -3.

therefore, C is the correct answer (the original f(x) - 3).

8 0

2 years ago

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

3 years ago

Simplify: (16-5)-9 x 1 A. 5 B. 2 C. 4 D. 3

Mariulka [41]

Answer:

B it right...

Step-by-step explanation:

4 0

3 years ago