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marissa [1.9K]
3 years ago
11

Find the quotient. I need help I am not very good with fractions sorry.

Mathematics
2 answers:
Georgia [21]3 years ago
5 0

Answer:

24/5                                               (Nothing wrong with that.)

Step-by-step explanation:

Dividing is multiplying with the second fraction flipped.

4/5 / 2/12 ----> 4/5 x 12/2

Multiply across. 4 x 12 = 48. 5 x 2 = 10.

Combine. 48/10.

Simplify (divide both sides by 2) . 24/5.

kozerog [31]3 years ago
5 0

Answer:

\frac{24}{5}

Step-by-step explanation:

To divide two fractions we turn the second fraction upside down and multiply two fractions afterwards

\frac{4}{5}  \div  \frac{2}{12}  =  \\  \frac{4}{5}  \times  \frac{12}{2}

now multiply 4 by 12 and 5 by 2

\frac{48}{10}

now simplify fraction if needed

\frac{24}{5}

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Answer:

Case n =5

z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894  

Case n =15

z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549  

Case n = 40

z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530  

P value

Case n =5

p_v =P(z  

Case n =15

p_v =P(z  

Case n =40

p_v =P(z  

Step-by-step explanation:

Data given and notation  

\bar X=4.8 represent the sample mean

\sigma=0.5 represent the population standard deviation

n sample size  

\mu_o =5 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is lower than 5, the system of hypothesis would be:  

Null hypothesis:\mu \geq 5  

Alternative hypothesis:\mu < 5  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

Case n =5

z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894  

Case n =15

z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549  

Case n = 40

z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530  

P-value  

Since is a left tailed test the p value would be:  

Case n =5

p_v =P(z  

Case n =15

p_v =P(z  

Case n =40

p_v =P(z  

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