<em><u>Complete Question:</u></em>
A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.
6H+ 4S> 74
This year, 8 hummingbirds pollinated the colony. What is the least number of sun birds that must pollinate the colony to ensure that it will survive until next year?
<em><u>Answer:</u></em>
The least number of sun birds is 7
<em><u>Solution:</u></em>
Given inequality is:
6H + 4S > 74
Where,
H is the number of hummingbirds
S is the number of sunbirds
This year, 8 hummingbirds pollinated the colony
Substitute H = 8 in given inequality
6(8) + 4S > 74
48 + 4S > 74
Subtract 48 from both sides
48 + 4S - 48 > 74 - 48
4S > 26
Divide both sides by 4
S > 6.5
Hence the least number of sun birds is 7
You will need to work left to right.
p - 10p + -5p +14p - -9p - 2 = -20
-9p + -5p +14p - -9p - 2 = -20
-14p +14p - -9p - 2 = -20
0p- -9p - 2 = -20
9p - 2 = -20
Then you will want to eliminate 2 by adding it to both sides
9p = -18
Then divide by 9 to isolate P
p=-2
Answer:
Perimeter=56 units
Area =196 square unites
Step-by-step explanation:
The diagonal would be 14√2.
The formula for area using the diagonal is 1/2d².
1/2x(14√2)²=1/2x196x2=196
For perimeter, s²+s²=392
2s²=392
s²=196
s=√196
s=14
14x4=56
$12.80 × 1.075 = $13.76
$13.76 × 1.15 =$15.82
Given:
Total number of senior students = 600
60% went on the senior trip.
One room was reserved for every 4 students.
To find:
The total number of reserved rooms.
Solution:
60% went on the senior trip from total 600 students. So, number of students who went on tripe is

Now, one room was reserved for every 4 students. So,



Therefore, the required number of reserved rooms were 90.