All categories

3 years ago

I'm a little bit confused about this question.

Mathematics

2 answers:

dlinn [17]3 years ago

7 0

The number 4 is in the ones place

1 3 4 . 0
thousand hundred ones

Virty [35]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Solve. 2a + 3b = 5 b=a5 a = 4 b = -1 a = 4 b=1

nikklg [1K]

Answer:

5 = 5 True

1 = 20 False

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$

Hence, our required probability is $\dfrac{1}{2}$

No, the answer is not $\dfrac{1}{3}$

5 0

2 years ago

12 to the power of 2 minus 6 to the power 2 times 3 to the power of 4 plus 5 to the power of 3?

Marina86 [1]

12^2 - 6^2 * 3^4 + 5^3

(144) - (36) * (81) + (125)
144 - (36 * 81) + 125
144 - 2916 + 125
-2,772 + 125
-2,647

5 0

3 years ago

Read 2 more answers

A bakery sells pastries in boxes of 7 each. If the bakery has 27 pastries, how many boxes can be filled?

skad [1K]

Answer:

3 with a few left over so 4

Step-by-step explanation:

4 0

2 years ago

You deposit $5000 in an account earning 8% interest compounded monthly. How much will you have in the account in 15 years?

Rasek [7]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &15 \end{cases}$

$\bf A=5000\left(1+\frac{0.08}{12}\right)^{12\cdot 15}\implies A=5000(1.00\overline{66})^{180}\implies A\approx 16534.61$

5 0

2 years ago