Why is multiplying with 6 like multiplying with 3

Mathematics

2 answers:

Burka [1]3 years ago

6 0

Its because 3 and 6 have the same factors

Aliun [14]3 years ago

6 0

Because three and six have the same factors

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Answer:

Answer B $(-\infty,1)U(1,2]$

Step-by-step explanation:

Notice that the quotient of f(x)/g(x) is:

$h(x)=\frac{\sqrt{2-x} }{x-1}$

therefore, this new function imposes conditions due to the fact that it has a square root in the numerator and a binomial in the denominator both with the variable x. Then, in order for the root in the numerator to be defined, the argument inside the root must be larger than or equal to zero. That is:

$2-x\geq 0\\2\geq x\\x\leq 2$

So, this condition must be satisfied by the x-values of the domain.

Then we have the binomial in the denominator, which in order to be defined needs to be different from zero. Notice that the only x-value that could cause problems (render zero) is:

$x-1=0\\x=1$