Eight hundred and ninety-six point eight hundred and fifty-four.
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Complete question :
A company has two manufacturing plants with daily production levels of 5x + 11 items and 2x - 3 items, respectively, where x represents a minimum quantity. The first plant produces how many more items daily than the second plant?
Answer:
3x + 14
Step-by-step explanation:
Given that:
Production level of plant 1 = 5x + 11
Production level of plant 2 = 2x - 3
The first plant produces how many more items daily than the second plant :
Plant 1 production - plant 2 production
(5x + 11) - (2x - 3)
Open the bracket :
5x + 11 - 2x + 3
5x - 2x + 11 + 3
3x + 14
Daily production of plant 1 exceeds that of plant 2 by 3x + 14
