Hello,
Let's assume a,b,c the 3 numbers
a+b+c=62
b=a-4
c=4*a
==>a+(a-4)+4a=62
==>6a=66
==>a=11
b=11-4=7
c=4*11=44
The 3 numbers are 11;7;44
Proofs:
11+7+44=62
7=11-4
44=4*11
I believe the correct answer is 15x + 5y =-1 but im not positive cause i did the problem and got -1 but the equation i got looks different i got the equation -15x + 5y = -1
These are the steps i followed
You always begin by the Given equation, which is in this case:
y+ = 3x
To remove the fraction, you multiply the whole equation by 5:
5y + 1 = 15x
Then, you move the "15x" the left-side of the equation, changing it's sign
-15x + 5y +1 = 0
You move the "1" to the right side, changing it's sign
-15x + 5y = -1
Answer:
Area = 30 in.
<h3>
Step-by-step explanation:</h3>
the formula for an area of a trapezoid is A = (a+b)/2 × h
a = base (or bottom)
b = 2nd base (or top)
h = height
set up your equation as A = (10 + 5)/2 × 4
A = 15/2 × 4
A = 7.5 × 4
A = 30
The area of the trapezoid is 30 in.
Hope this can help you understand
3.3n- 6.7
I hope this is the answer to your solution