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Molodets [167]
3 years ago
10

Claire is ordering trophies for her school. Company A charges $4.50 for each trophy and a one-time engraving fee of $26. Company

B charges $8.50 for each tu trophy and a one-time engraving fee of $18. Which inequality can be used to find x, the minimum number of trophies than can be ordered so that the total charge at Company A is less than the total charge at Company B
A. 4.5 + 26x < 8.5 + 18x
B. 4.5 + 26x > 8.5 + 18x
C. 4.5x + 26 > 8.5x + 18
D. 4.5x + 26 < 8.5x + 18​
Mathematics
1 answer:
Ugo [173]3 years ago
5 0

Answer:

my putyy

Step-by-step explanation:

ong its my putty hehehe

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How to graph y = 2|x + 3| - 4
mr_godi [17]

The x-intercepts and the y-intercepts of the function is that determines the graph is:

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<h3>How do we graph the function y = f(x) of an absolute equation?</h3>

The function of an absolute equation can be graphed by determining the values of x-intercepts and the y-intercepts of the function.

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brainly.com/question/2166748

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8 0
1 year ago
The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?
adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)

\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t  \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}

$$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$$

3 0
2 years ago
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