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diamong [38]
3 years ago
8

find the unit rate for number of parts manufactured per hour if 1630 parts are made in 6 hours. round to the nearest integer

Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0
They make around 272 parts per hour. Hope i helped. :)
Romashka-Z-Leto [24]3 years ago
4 0
The answer is 272 parts per hour
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Together, Steve and Tom sold 86 raffle tickets for their school. Steve sold 14 more than twice as many raffle tickets as Tom. Ho
bonufazy [111]

86= Steve + Tom

Steve= 14+2(Tom)

86= (14+2T) + T

86-14 = 3T

62 = T

Steve sold 62 tickets

86-62 = 24 tickets Tom sold




3 0
3 years ago
3.920 * (1.018)^x = 5.500<br><br>X=?​
Andrei [34K]

Answer:

19

Step-by-step explanation:

3.920(1.018)ˣ = 5.500

  • First we can divide both sides by 3.920 to get: (1.108)ˣ = 1.403
  • Then we can take the natural log of both sides to get: ln[(1.108)ˣ] = ln(1.403)
  • We can then use logarithmic rules to move the x exponent to the front: xln(1.108) = ln(1.403)
  • Then we can divide both sides by ln(1.108) to get: x=\frac{ln(1.403)}{ln(1.018)}
  • Then using a calculator we get x = 18.98 ≈19
5 0
3 years ago
Simplify the following surd:-
Phoenix [80]

Step-by-step explanation:

1/4 √243 + √27/4 =

(¼ √81×3) + (¼ √9×3) =

9/4 √3 + 3/4 √3 =

12/4 √3 =3√3

8 0
3 years ago
What is the speed, in meters per second, of a paper airplane that flies 24 meters in 6 seconds?
Rama09 [41]

In order to find the answer to this question you will have to divide 24 and 6.

24\div6

24\div6=4

=4

Therefore the paper airplane flies "4 meters every second."

Hope this helps.

6 0
3 years ago
Read 2 more answers
An object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seco
bulgar [2K]

Answer:

y=2\text{cos}((\frac{2\pi}{3})t)

Step-by-step explanation:

We have been given that an object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seconds. We are asked to find the cosine function that can be used to model the height of the object.

We know that standard form of cosine function is y = A\cdot \text{cos}(Bt-C)+D, where,

|A| = Amplitude,

Period = \frac{2\pi}{|B|},

C = Phase shift,

D = Vertical shift.

Since distance between maximum and minimum is 4, therefore, amplitude will be half of it, that is, A = 2.

Since objects gets back to its maximum value in every 3 seconds, therefore, period of the function is 3 seconds. We know that period is given by \frac{2\pi}{|B|}, therefore, we can write \frac{2\pi}{|B|}=3, therefore, B = \frac{2\pi}{3}.

We haven't been given any information about phase and mid-line, we can assume the values of C and D to be zero .

Therefore, our function required function would be y=2\text{cos}((\frac{2\pi}{3})t).

6 0
4 years ago
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