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3 years ago

7

Graph a parabola whose xxx-intercepts are at x=-3x=−3x, equals, minus, 3 and x=5x=5x, equals, 5 and whose minimum value is y=-4y

=−4y, equals, minus, 4.

1 answer:

DENIUS [597]3 years ago

7 0

Answer:

Vertex: (1, -4)

intercept: (-3, 0)

Step-by-step explanation:

lets be real, you don't care about an explanation you just want the answer.

BUT... the vertex is the Y line and the Intercept is the X line

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3x + y = 8<br><br> -x + y = -4<br> Solve the system. Write your answer as an ordered pair (x, y)

timurjin [86]

I hope this helps you

x=y+4

3 (y+4)+y=8

3y+12+y=8

4y= -4

y= -1

x= -1+4

x=3

(3, -1)

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4 years ago

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statuscvo [17]

Answer:

the required value which is equal to

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Step-by-step explanation:

here's the explanation in attachment.

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3 years ago

Can you explain how to do this correctly?

iVinArrow [24]

8/x-7=7/2
16=7(x-7) cross multiply
16=7x-49
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Alternative form
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Which is 1st options in your questions.

Hope this helps!

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3 years ago

what is the probability of spinning the spinner three times and having all three spins be greater then 5? Spinner is labeled 1-8

lilavasa [31]

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3 years ago

Rob and casey are batting practice . The table below shows the joint relative frequencies for their misses , fouls ,hits and hom

serious [3.7K]

Answer:

$P(Homeroom|Casey)= \frac{1}{21}$

$P(Rob|Hit)= \frac{23}{50}$

Step-by-step explanation:

Hello!

1)

Given the table of probabilities you have to calculate the conditional probability that the result was a homeroom given that Casey was batting.

Following the general model you can calculate this probability as:

$P(A|B) = \frac{P(AnB)}{P(B)}$

Given two events A and B that are not independent, the probability of A given that B has occurred is equal to the division between the intersection between A and B by the probability of B.

In terms of this excersise:

$P(Homeroom|Casey)= \frac{P(HomeroomnCasey)}{P(Casey)}$

Reading the table, the "P(Casey)" is found on the marginals of the table, is calculated as the summation of all battings done by Casey:

P(Casey)= 0.1125+0.05+0.3375+0.025= 0.525

P(Homeroom∩Casey)= 0.025

$P(Homeroom|Casey)= \frac{P(HomeroomnCasey)}{P(Casey)}= \frac{0.025}{0.525} = \frac{1}{21}= 0.0476$

2)

You have to calculate the probability of the batting being made by Rob given that it was a hit.

$P(Rob|Hit)= \frac{P(RobnHit)}{P(Hit)}$

The probability of the intersection is

P(Rob∩Hit)= 0.2875

P(Hit)= 0.2875+0.3375= 0.625

$P(Rob|Hit)= \frac{P(RobnHit)}{P(Hit)}= \frac{0.2875}{0.625} = \frac{23}{50} = 0.46$

I hope this helps!

4 0

3 years ago