Please help me with this problem 3.14 = 22/7 and r = 7/4

Mathematics

1 answer:

nevsk [136]3 years ago

8 0

What is actually the question here?

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The length of a rectangle is 3 less than 2 times the width if the perimeter is 60 what is the length

Semenov [28]

P=2w+(2w-3)
60=4w-3
63=4w
15.75=w

l=2w-3
l=(2×15.75)-3
l=31.5-3
l=28.5

This answer doesn't add up so if you meant the COMBINED width then:

P=w+(2w-3)
60=3w-3
63=3w
21=w

l=2(21)-3
l=42-3
l=39

(This answer checks out so this is probably what you meant hope I helped)

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Sarah:

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