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Iteru [2.4K]
3 years ago
12

X² + 6x – 27=0 What is the answer for this question

Mathematics
2 answers:
Tju [1.3M]3 years ago
7 0
(x+9)(x-3)=0
x = 3,-9
muminat3 years ago
6 0
The answer is X1=-9,X2=3
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What is the approximate solution to this equation?
Sindrei [870]

Answer: b)

Step-by-step explanation:

3^3 is equal to 27 exactly, but it asks for an approximate. 27.55 is near 27 so yea, there ya go ^

5 0
4 years ago
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Please help me out here ASAP. Thanks!
GuDViN [60]
   y - y₁ = m(x - x₁)
y - (-1) = 4[x - (-3)]
   y + 1 = 4(x + 3)
   y + 1 = 4(x) + 4(3)
   y + 1 = 4x + 12
       - 1           - 1
         y = 4x + 11

The answer is B.
4 0
4 years ago
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5 0
3 years ago
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Find the value of x if it is a number between 8 and 12 exclusive.​
sergij07 [2.7K]

Given:

x is a number between 8 and 12 exclusive.​

To find:

The value of x.

Solution:

It is given that x is a number between 8 and 12 exclusive.​ It means the value of x lies between 8 and 12 but 8 and 12 are not included.

8

The whole numbers for 8 range are 9, 10, 11.

Therefore, the values of x are 9, 10, 11 and the value of x in the form of inequality is 8.

6 0
3 years ago
Simplify (1 − cos x)(1 + cos x). (2 points)
Vadim26 [7]

Answer:

sin²x

Step-by-step explanation:

we have

(1 − cos x)(1 + cos x)=1-cos²x

Remember that

sin²x+cos²x=1 ------> i-cos²x=sin²x

therefore

(1 − cos x)(1 + cos x)=sin²x

4 0
3 years ago
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