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SVETLANKA909090 [29]
3 years ago
11

Check all statements that are equivalent to If the sky is not clear, then you don't see the stars ? a. Clear sky is necessary an

d sufficient for seeing the stars. ? b. If the sky is clear, then you see the stars. c. You don't see the stars unless the sky is clear. ? d. Clear sky is necessary to see the stars. e. The sky is clear only if you see the stars. f. Clear sky is sufficient to see the stars. g. If you don't see the stars, then the sky is not clear. h. If you see the stars, then the sky is clear. i. You see the stars only if the sky is clear.
Mathematics
2 answers:
IrinaVladis [17]3 years ago
6 0

Answer: The answer is G

Step-by-step explanation:

If you don't see the stars, then the sky is not clear. This statement is equivalent to saying "If the sky is not clear, then you don't see the stars", because if you rearrange both statements you will find out that they are equivalent to each other.

Mark out all the words in each statement, you will discover that at the end you will have no word left on both side, its just as good as saying 1 - 1 = 0.

JulijaS [17]3 years ago
3 0

Answer:

G

Step-by-step explanation:

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Convert 8^12 = 3x - 5 to corresponding logarithmic function.
julia-pushkina [17]

Answer:

Step-by-step explanation:

8^{12}=3x-5\quad :\quad x=\frac{8^{12}+5}{3}\quad \left(\mathrm{Decimal}:\quad x=22906492247\right)

8^{12}=3x-5\\\\\mathrm{Add\:}5\mathrm{\:to\:both\:sides}\\3x-5+5=8^{12}+5\\Simplify\\\mathrm{Divide\:both\:sides\:by\:} 3\\\frac{3x}{3}=\frac{8^{12}}{3}+\frac{5}{3}\\\mathrm{Simplify}\\x=\frac{8^{12}+5}{3}

6 0
3 years ago
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Find the solution set of the inequality 14- 3x < -1.14
Brrunno [24]

Answer:

14-3x<-1.14

-3x<-1.14-14

-3x<-15.14

x<5.04

8 0
3 years ago
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If and , find .<br><br> A. <br> B. <br> C. <br> D.
trapecia [35]
Answer: option D. 2x^2 + (3/2)x  - 5

Explanation:

1) polynomials given:

 f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3

2) question: find (f + g) (x)

That means that f(x) + g(x), so you have to add up the two polynomials given.

3) x/2  - 2 + 2x^2 + x - 3

4) Combine like terms:

a) terms with x^2: you only have 2x^2, so it is not combined with other term.

b) terms with x: x/2 + x

that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x

c) constant terms: - 2 + (-3) = - 2 - 3 = - 5

5) Result: 2x^2 + (3/2)x - 5

That is the option d.


4 0
3 years ago
Solve 7x - 2(x + 1) = 6x + 14 <br><br> A) -12 <br><br> B) 12<br><br> C) -16<br><br> D) 16
anzhelika [568]
<span>7x - 2(x + 1) = 6x + 14 
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6x - 5x = -2 - 14
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answer
</span><span>C) -16</span>
3 0
3 years ago
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