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Anna11 [10]
3 years ago
6

The trail is a loop that is 3/4 of a mile long. On Monday, Selma land the loop in 1/6 of an hour. What is selmas unit rate in mi

le per hour?
Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

1/10

Step-by-step explanation:

3/4 add 1/6

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Answer:

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Step-by-step explanation:

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torisob [31]

Answer:

x = 15.7945

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
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<u>Trigonometry</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

Angle θ = 33°

Opposite Leg = <em>x</em>

Hypotenuse = 29

<u>Step 2: Find Angle</u>

  1. Substitute in variables [sine]:                                                                           sin33° = x/29
  2. [Multiplication Property of Equality] Multiply 29 on both sides:                    29sin33° = x
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  4. Evaluate:                                                                                                           x = 15.7945
7 0
3 years ago
Carrie and brent leave home at the same time. carrie drives due east at a rate of 30 mph, while brent drives due south at a rate
Helga [31]

<h3>They are 268 miles far apart after 4 hours</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<u>Given :</u>

v₁ = 30 mph due east

v₂ = 60 mph due south

t = 4 hours

<u>Unknown :</u>

displacement = d = ?

<u>Solution :</u>

d_1 = v_1 \times t

d_1 = 30 ~ mph \times 4 ~ h

d_1 = \boxed {120 ~ miles}

d_2 = v_2 \times t

d_2 = 60 ~ mph \times 4 ~ h

d_2 = \boxed {240 ~ miles}

d^2 = (d_1)^2 + (d_2)^2

d^2 = 120^2 + 240^2

d^2 = 72000

d = \sqrt{72000}

d = 120\sqrt{5} ~ miles

d \approx \boxed {268 ~ miles}

<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

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