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notka56 [123]
3 years ago
9

Fully answer BOTH questions a and b below.

Mathematics
1 answer:
Setler [38]3 years ago
6 0
A. 540 is 60% of 900 so 900 people were surveyed.
60/100 • x= 540
Multiply both sides by 100
Then divide both sides by 60

B. If you subtract 900-540 your answer will be 360. 360 people preferred running.
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Graph the linear function using the slope and y-intercept.<br> y=1/3x+3
hammer [34]

Answer:

Graphed this on desmos, hope it helped!!

Step-by-step explanation:

8 0
2 years ago
Help me plz plz will mark branliest
Ksenya-84 [330]

Step-by-step explanation:

On the first question, you would want to put the equation together. To find x you will put 2x+6=40. Subtract 6 on both sides and you will find your x value.

7 0
2 years ago
A rectangular box is 6 inches wide 10 inches long and 2 inches tall how much wrapping paper is needed to cover the box exactly
stepladder [879]

Answer:

184 in²

Step-by-step explanation:

Given :

Width, w = 6 inches

Length, l = 10 inches

Height, h = 2 inches

To obtain how much wrapping paper is needed ; we take the surface area of the box

Surface area = 2(lw + lh + wh)

Surface area = 2((6*10) + (6*2) + (10*2))

Surface area = 2(60 + 12 + 20)

Surface area = 2(92)

Surface area = 184 in²

The amount of wrapping paper needed = 184 in²

7 0
3 years ago
Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
3 years ago
Read 2 more answers
One angle of the following triangle measures 2x. How many degrees does that angle
ella [17]

<u>Given</u><u> info</u><u>:</u><u>-</u> In triangle (∆)ABC , in which ∠A = 2x, ∠B = x+15° and ∠C = 2x + 10°. Then find the value of x , also find the measure of each angles of a triangle.

<u>Explanation</u><u>:</u><u>-</u>

Let the angles be 2x, x+15 and 2x+10 respectively.

∵ Sum of the three angles of a triangle is 180°

∴ ∠A + ∠B + ∠C = 180° [Sum of ∠s of a ∆=180°]

→2x + x+15 + 2x+10 = 180°

→ 2x + x + 2x + 15 + 10 = 180°

→ 3x + 2x + 15 + 10 = 180°

→ 5x + 15 + 10 = 180°

→ 5x + 25 = 180°

→ 5x = 180°-25

→ 5x = 155°

→ x = 155°÷5 = 155/5 = 31.

Now, finding the measure of each angles of a ∆ABC by putting the original value of “x”.

∴ ∠A = 2x = 2(31) = 62°

∠B = x+15 = 31 + 15 = 46°

∠C = 2x + 10 = 2(31) + 10 = 62 + 10 = 72°.

3 0
3 years ago
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