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gregori [183]
3 years ago
6

Please help me with both parts?

Mathematics
1 answer:
Neko [114]3 years ago
4 0
I'm willing to help you with both parts
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What is the value of n in the equation below?<br><br>A:-20<br>B:-9<br>C:9<br>D:20
Nikitich [7]
Answer is C:9
12^9/12^5 = 12^4

hope it helps
8 0
3 years ago
Read 2 more answers
Halla el área de un triángulo equilátero de 54 cm de perímetros
adoni [48]

Answer:

Area of equilateral triangle = 81√3 cm²

Step-by-step explanation:

Given:

Perimeter of an equilateral triangle = 54 cm

Find:

Area of equilateral triangle

Computation:

Perimeter of an equilateral triangle = 3 x Side

54 = 3 x Side

Side of equilateral triangle = 54 / 3

Side of equilateral triangle = 18 cm

Area of equilateral triangle = [√3/4]side²

Area of equilateral triangle = [√3/4][18]²

Area of equilateral triangle = [√3/4][324]

Area of equilateral triangle = [√3][81]

Area of equilateral triangle = 81√3 cm²

5 0
3 years ago
What is the length of the dotted line in the diagram below? Leave your answer in simplest radical form.
Pachacha [2.7K]

Answer:

\sqrt{93}

Step-by-step explanation:

8^2+5^2=c^2

64+25=c^2

89=c^2

c=\sqrt{89} <-- this is the length of the rectangle at the bottom

2^2+(\sqrt{89})^2=c^2

4+89=c^2

c=\sqrt{93}  <-- length of dotted line (diagonal)

6 0
2 years ago
Read 2 more answers
Solve the equation
inysia [295]

Answer:

x ≈ 1.32, x ≈ - 5.32

Step-by-step explanation:

Given

x² + 4x - 7 = 0 ( add 7 to both sides )

x² + 4x = 7

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 7 + 4

(x + 2)² = 11 ( take the square root of both sides )

x + 2 = ± \sqrt11} ( subtract 2 from both sides )

x = - 2 ± \sqrt{11}

Thus

x = - 2 - \sqrt{11} ≈ - 5.32 ( to 2 dec. places )

x = - 2 + \sqrt{11} ≈ 1.32 ( to 2 dec. places )

8 0
3 years ago
Read 2 more answers
How do I find one side of an angle
Dimas [21]

Answer: Can you explain more? you have to calculate it by an theorm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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