If the 4 states have to be in a specific order say ABCD,
then the total number of different possible routes is:
43P4 = 2,961,840
So the probability is:
1 / 2,961,840 = 3.38 x 10^-7
But if the 4 states can be in any order such as DBAC,
ACBD etc, then the total number of different possible routes is:
43C4 = 123,410
So the probability is:
1 / 123,410 = 8.1 x 10^-6
No I don’t think it is practical to list all the
different possible routes to select the one that is best. We can simply use
mathematical models to solve for that one.
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3 + |t + 4| < 10
Subtract 3
|t + 4| < 7
Because it is absolute value...
t + 4 < 7 AND t + 4 > -7
t < 3 AND t > -11
ANSWER:
t < 3 AND t > -11
51cm / 3 X 5 = 85cm
Jijdididjdidjdjdjd
25(6) + [8(6-s)] = t, where s = number of hours and t = total.
7 + 5 = 12
180 / 12 = 15
7 x 15 = 105
5 x 15 = 75
£105 : £75
