What is the vertex of a circle in the equation of a circle?

Mathematics

1 answer:

anastassius [24]4 years ago

8 0

<span> Move to the right side of the </span>equation<span> by adding to both sides.</span>

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Find the value of x in the isosceles triangle shown.

strojnjashka [21]

Answer:

x = 7

Step-by-step explanation:

Given the base of the triangle is 6 and the line dividing the triangle is x. To get x divide the triangle into two equal halves. When you do so,you’ll have a right triangle with x as the opposite , 8 as the hypotenuse and the adjacent as 3.

Using Pythagoras theorem, we have

8^2 = x^2 + 3^2

8 x 8 = x^2 + 3 x 3

64 = x^2 + 9

Subtract 9 from both sides

64 - 9 = x^2 + 9 - 9

55 = x^2

X^2 = 55

x = squared root of 55

x = 7.4

x = 7

8 0

4 years ago

66253 divided by 317

garik1379 [7]

You get 209, when you divide 66253 by 317

7 0

3 years ago

Read 2 more answers

Can someone help me with this question ? Show steps please

jek_recluse [69]

Answer:

B) $\boxed{A_T=108\;in^2}$

Step-by-step explanation:

That is a triangular prism and thus, it has two bases that are triangles, in this case, right triangles, whose hypotenuse is 5 in. long and one of its legs is 4 in. and the other one, 3 in.

The first step is to find the area of both bases like this:

$A_B=2\left(\dfrac{b\cdot h}{2}\right)=b\cdot h=4\cdot 3\\\\ \boxed{A_B=12\;in^2}$