Okay, so total dogs are 49.
So we know if x=large dogs and y=small dogs, then x+y=49.
Next we are told that there are 36 MORE small dogs than large dogs. We can take that more meaning addition, and x being our value for large dogs. So y=x+36.
After that we now know what value we can plug in for y. So x+x+36=49.
We can then simplify it to 2x+36=49.
Subtracting the 36 from both sides, leaves you with 2x=13.
Followed by dividing both sides by 2, gives you x=6.5. Or 6.5 large dogs.
Now we can plug this into our formula for the small dogs (y=x+36) to give us y=6.5+36, which simplifies to y=42.5. Or 42.5 small dogs. Which is our answer.
We can double check it by adding the small and large dogs together, 6.5+42.5, which gives us 49, our total entries.
Answer:
3:the value of the 4 in 0.04 is the value of the 4 in 0.4 divided by 10.
Step-by-step explanation:
This is because in decimal places, we have what is called place value. In a decimal number after the decimal point, each number place is divided by an increasing power of 10. So, for example, if we have a decimal number 0.82, the place value of the 8 is 8/10 while that of the 2 is 2/10² = 2/100.
So, in the given numbers, 0.04 has a place value of 4/100 and 0.4 has a place value of 4/10. So, we can see that 4/100 = 4/10 ÷ 10 = 4/10 × 1/10.
So, the value of the 4 in 0.04 is the value of the 4 in 0.4 divided by 10.
Consider this option:
1. area_rombus=a*h, where a=6 - the length of the side, h - height.
h=area_rombus/a.
2. area_sq=a², where a=6 - the length of the square.
area_sq=36, area_rombus=4/5 *36=28.8.
3. according to the item 1 h=area_rombus/a=28.8/6=4.8.
answer: 4.8
A) the greatest common factor is how to factors something
for this case x is the gcf
x(x^2 - 4) is the answer
B) Cannot be factored there is no common factor.
