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miskamm [114]
3 years ago
8

Help againnn. Yes, I’m kinda slow

Mathematics
1 answer:
Leni [432]3 years ago
5 0

So, the right option is 1. so if my ans was helpful u can follow me.

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1285 students went on a field trip six buses were filled with the same number of students and seven other student travel in coll
Mademuasel [1]
213 students were in each bus
6 0
3 years ago
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A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
6 - 8x = 6x - 9x + 11
mars1129 [50]

6-8x=-3x+11

-8x+3x=11-6

-5x=5

x=-1

The first step is to isolate the variable, then you solve. Hope this helps, brainliest if you can.

6 0
2 years ago
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Ten times the sum of half a number and 6 is 8
nexus9112 [7]
Let the required number is 2x ,





According to the condition,



➡ 10 times the sum of half of 2x and 6 = 8

= > 10 \times ( \frac{2x}{2} + 6) = 8 \\ \\ \\ = > 10 \times (x + 6) = 8 \\ \\ \\ = > 10x + 60 = 8 \\ \\ \\ = > 10x = 8 - 60 \\ \\ \\ = > 10x = - 52 \\ \\ \\ = > x = - \frac{ 52}{10} \\ \\ \\ = > x = - 5.2



Therefore the value of x is -5.2


And, required number is -5.2
3 0
3 years ago
Plz help me with it !
Kipish [7]

Answer:   \bold{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt{2}}

<u>Step-by-step explanation:</u>

\dfrac{\sqrt7-5}{\sqrt7+\sqrt8}\bigg(\dfrac{\sqrt7-\sqrt8}{\sqrt7-\sqrt8}\bigg)=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{7-8}=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{-1}\\\\\\=\boxed{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt2}

8 0
3 years ago
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