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ladessa [460]
3 years ago
5

Find the Area of the triangle.

Mathematics
2 answers:
Marina86 [1]3 years ago
5 0

Answer:56 square units

Step-by-step explanation:

area of a triangle=1/2*base*height

1/2*8*14=56 square units

OlgaM077 [116]3 years ago
5 0

Answer: The answer is 56 square units.

Step-by-step explanation: 14 x 8 = 112. Because a triangle is half of a sqaure, you divide 112 by 2. The answer is 56.

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Find the midpoint of the line segment joining the points ​(-1​,​-1) and ​(-3​,​12).
gregori [183]

Answer:

(-2, 11/2)

Step-by-step explanation:

use the mid-point formula!

((x1+x2)/2, (y1+y2)/2)

((-1+-3)/2, (-1+12)/2)

(-2, 11/2)

8 0
3 years ago
!!!!!!!( help me solve this problem)!!!!!!!
ruslelena [56]
Hi Bre,

Since lines a and b are parallel, we know that in the image:
- ∡1 ⇔ ∡5
- ∡2 ⇔ ∡6
-       ...
- ∡4 ⇔ ∡8

We're given the angle of ∡7, which is 114°.  We can see that ∡7 + ∡8 will equal to 180° (since line b is a straight line) and since ∡8 ⇔ ∡4, we can deduct that ∡7 + ∡4 = 180°.

From here, it's just imputing the information and solving.
⇒ 114° + ∡4 = 180°
⇒ ∡4 = 180° - 114°
⇒ ∡4 = 66°

-Hope this helps!
6 0
3 years ago
Read 2 more answers
The corr standard form for 100000+2000+500+150+17+0.08
kari74 [83]
<span>100000 + 2000 + 500 + 150 + 17 +0.08

= 102000 + 500 + 150 + 17 + 0.08

= 102500 + 150 + 17 + 0.08

= 102650 + 17 + 0.08

= 102667 + 0.08

= 102667.08 <--</span>
7 0
3 years ago
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Simplify (125)^-2/3 with positive exponents and no radicals <br>show all work.<br>PLEASE HELP
Reptile [31]
For this case, what you should keep in mind are the following considerations:

 1) Rewrite the expressions correctly using the properties of the exponents: Addition, multiplication, division, subtraction and negative exponents.

 2) Simplify the expression as much as possible.

 Answer:
 See attached image.

3 0
3 years ago
Anyone plz help me I am sooo confused
belka [17]

Answer:

3.

Step-by-step explanation:

The scale factor is basically what figure B is divided by.

9 / 3 = 3

3.6 / 3 = 1.2

8 0
3 years ago
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