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DiKsa [7]
3 years ago
9

Please and thank you

Mathematics
2 answers:
MakcuM [25]3 years ago
7 0

Answer:

twenty-four more than twelve times a number

Step-by-step explanation:

algol [13]3 years ago
6 0

Answer:

the last one

Step-by-step explanation:

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Can someone help....
bulgar [2K]

Answer:

-16

Step-by-step explanation:

5 0
3 years ago
Could anyone tell me where these numbers would go? domain or range?
Free_Kalibri [48]
Independent, x-coordinate, input, domain.
Dependent, y-coordinate, output, range.

Domain: {0.5, 1, 4, 6, 8}
Range: {1, 1.5, 10, 12, 18}
8 0
3 years ago
Find the arc length, x, when
Arte-miy333 [17]

The arc length of the circle is 5π/9 units

<h3>How to determine the arc length?</h3>

From the question, we have the following parameters

Angle, ∅ = 5π/9

Radius, r = 1 unit

The arc length (x) is calculated as

x = r∅

Substitute the known values in the above equation

x = 5π/9 * 1

Evaluate the product

x = 5π/9

Hence, the arc length of the circle is 5π/9 units

Read more about arc lengths at:

brainly.com/question/2005046

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5 0
2 years ago
I need an answer really quick.
saul85 [17]

Answer:

Switch to the other streaming service

Step-by-step explanation:

So, 96$ with a 12% increase is $107.52.

But if you do 8.75×12 you get $105.

So Clare should switch to the other music stream.

8 0
3 years ago
The equation 12x² + 4kx + 3 = 0 has real and equal roots, if
sleet_krkn [62]

Answer:

k=\pm3

Step-by-step explanation:

[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant \Delta = b^2-4ac (or, if b is an even number, 1/4 of it) is zero.

<u>I see it! I see it!</u>

Stare at it for a while. First term is 3(2x)^2, third term is 3(1)^2, we are missing a double product, but we can play with k. For the LHS to be 3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3 you just need 4k= \pm12 \rightarrow k=\pm3.

<u>I don't see it...</u>

Then number crunching it is. Set the discriminant to 0, solve for k

\frac{\Delta}4 = 4k^2-12\cdot 3 =0 \rightarrow 4k^2=36 \\k^2 = 9 \rightarrow k=\pm3

8 0
2 years ago
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