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Vedmedyk [2.9K]
3 years ago
10

Solve for ,×. Then, circle whether each angle pair is complementary or supplementary.​

Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0

See the solution above..☝☝

HOPE THIS WILL HELP!!!

<h3>PLZZ PLZZ MARK ME BRAINLIEST!!</h3>

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Pls help I will award brainiest
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Answer:

189

Step-by-step explanation:

ratio is 8:9

multiply ratio by 21 to get 168:189

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The ordered pairs represent a function.
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(0,-1)(1,0)(2,3)(3,8)(4,15)
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slava [35]

Answer:

2:1

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There are 14 spoons (not sure what they are) and 7 eyes so it is 14:7

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4 0
3 years ago
Read 2 more answers
What is the total resistance of a parallel circuit that has two loads? Load one has a resistance of 10 ohms. Load two has a resi
Romashka-Z-Leto [24]

Answer:

The total resistance is 7.0588\Omega

Step-by-step explanation:

Attached please find the circuit diagram. The circuit is composed by a voltage source and two resistors connected in parallel: R_1=10\Omega and R_2=24\Omega.

First step: find the total current

For finding the current that the voltage source can provide, you must find the current consumed by each load and then add both. To do that, take first into account that the voltage is the same for both resistors (R_1 and R_2).

  • I_{R_1}=\frac{V_S}{R_1}
  • I_{R_2}=\frac{V_S}{R_2}

The total current is:

I_{TOTAL}=I_{R_1}+I_{R_2}=\frac{V_S}{R_1}+\frac{V_S}{R_2}=\frac{R_2\cdot V_S+R_1\cdot V_S}{R_1\cdot R_2}

I_{TOTAL}=V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}

Now, the total resistance (R_{TOTAL}) would be the voltage divided by the total current:

R_{TOTAL}=\frac{V_S}{I_{TOTAL}}

If you replace I_{TOTAL} by the expression obtained previously, the total resistance would be:

R_{TOTAL}=\frac{V_S}{V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}}

After simplifying the terms you should get:

R_{TOTAL}=\frac{R_1\cdot R_2}{R_1 + R_2}}

Now, you must replace the values of the resistors:

R_{TOTAL}=\frac{(10\Omega )\cdot (24\Omega)}{10\Omega + 24\Omega}}=\frac{120}{17}\Omega=7.0588\Omega

Thus, the total resistance is 7.0588\Omega

3 0
3 years ago
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