Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:(x,y)=(2.5,1)
Step-by-step explanation:
Given
thus on comparing
2x+y=6------1
On comparing exponent of 2
------2
we get x=2.5
substitute x in 1
y=1
(x,y)=(2.5,1)
Answer:4+x/3=2
Step-by-step explanation:
4 more=4+
the quotient of a number and 3= x/3
the anwser = =2
Huh? there can't be 4 zeroes. but if u mean 140,000,000,000; then it's 140 billion.
it u mean 14,000,000,000; then that's 14 billion.
