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2 years ago

PLEASE HELP ASAP!!! :)

1 answer:

6 0

The rule of the transformation is
(x,y)->(-y,x)
which corresponds to a 90 counterclockwise rotation about the origin,
which in turn corresponds to a 270 clockwise rotation about the origin.

Note that all rotations preserve lengths and angles, hence the image and preimage are congruent.

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Which is a counterexample of the following conjecture: "If two angles are supplementary, they have the same measure?"

Marrrta [24]

Answer:i dont know but i think its D.

Step-by-step explanation:

Pls mark meh Brainlessed

My friend justen here hes tacken and hes cracked at fornight my guy AHHHH A BREAD DOG

4 0

2 years ago

The "middle" term of a trinomial form of (3x+1)(x-4) is:

Zarrin [17]

Answer:

Expand the following expression

(3x+1)(x-4) = 3x^2-12x+x-4

middle term = -11x

3 0

1 year ago

Help me with question 7 pls

Marrrta [24]

If the coefficient of x^2 is negative, the graph will be n shaped and curve down instead of like a u shape if it was positive. If the vertex is below the x axis and curves down, it won’t pass the x axis, Tia is right.

5 0

2 years ago

In a rectangular coordinate plane what is the distance between points (-3,0) and (3,8)

zheka24 [161]

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:

$\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

"d" represents the distance and coordinates are expressed as follows: (x, y)

Let's go to the calculations.

$\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\ \mathsf{d=\sqrt{(3-(-3))^2+(8-0)^2}}\\\\ \mathsf{d=\sqrt{(3+3)^2+(8)^2}}\\\\ \mathsf{d=\sqrt{(6)^2+64}}\\\\ \mathsf{d=\sqrt{36+64}}\\\\ \mathsf{d=\sqrt{100}}\\\\ \underline{\mathsf{d=10}}$

The answer is 10 uc.

8 0

3 years ago

part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

Step-by-step explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

5 0

2 years ago