Answer:
the worth after 15 years is $7,783.29
Step-by-step explanation:
Given that
The purchase price is $16,800
It would be depreciated 5% per year
We need to find out the worth after 15 years
= $16,800 × (1 - 0.05)^15
= $16,800 × 0.46329123
= $7,783.29
Hence, the worth after 15 years is $7,783.29
In this way it should be determined
The probability that a person wins the game is 32.1%
<h3>How to illustrate the probability?</h3>
Based on the information given, the following can be depicted. It should be noted that there are 6 sides as well as 4 cards.
Therefore, the numbers on the dice i.e from 1 - 6 will be represented 4 times each. This gives a total of (4 × 6) = 24. There are also 4 cards. The total in sample space will now be:
= 24 + 4 = 28
The frequency table will be such that 28 or more has a relative frequency of 9. Therefore, the probability that a person wins the game will be:
= 9/28 = 32.1%
When you win 25% of the time, this illustrates that the number of products picked will be:
= 25% × 28
= 7 products.
The probability of participants achieving a winning score of 36 or higher in four consecutive attempts will be:
= 1/6⁴
= 1/1296
Learn more about probability on:
brainly.com/question/24756209
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Answer:
Step-by-step explanation:
Distance = the square root of (x2-x1)2 + (y2-y1)2Added:Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squared
Answer:
Step-by-step explanation:
The weight of an object on Moon is 6 times smaller than same on Earth.
<u>If it weights 18/5 kg on Earth then its weight on Moon is:</u>
There are 4 possible outcomes based on 2 types of wash (deluxe wash & other wash) and 2 vacuum uses (with vacuum and no vacuum). Since customers are equally likely to choose between these, we can run a uniform distribution from 1-4, where each represents one outcome. For example, 1 = deluxe+vacuum, 2=deluxe+no vacuum, 3=other wash+vacuum, 4=other wash+no vacuum. Then after running a large number of simulations (ex. 1000), count the number of the desired result (which is the number 2), and divide by the total number. This will give the probability.
