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almond37 [142]
2 years ago
13

If the standard deviation of a data set were originally 8, and if each value in

Mathematics
1 answer:
irina1246 [14]2 years ago
6 0
The correct answer would be C. or 14
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The measure of angle ABD is 105º. The measure of angle ABC is 75º.
MakcuM [25]

If we know that the WHOLE angle added is 105 and only part is 75 you need to subtract the whole angle and subtract from part of the whole angle.

105-75=30. You get 30 And that’s you answer!

Picture to help with your understanding.

5 0
3 years ago
X^2 + 7x – 18 = 0<br> a<br> {–2, 9}<br> b<br> {–9, 2}<br> c<br> {2, 9}<br> d<br> {–2, –9}
Sedaia [141]

Answer:

b)-9,2

Step-by-step explanation:

x^2+7x-18=0

x^2+9x-2x-18=0

x(x+9)-2(x+9)=0

(x+9)(x-2)=0

therefore

x=-9

x=2

6 0
2 years ago
Need help with this problem explain pls
Usimov [2.4K]
All sides of an equilateral triangle are equal, so all three sides are 9 cm.
To find h, use the pythagorean theorem. This requires use of only one right triangle, where we use b as our h.

a^2+b^2=c^2
(4.5)^2+b^2=(9)^2
(20.25)+b^2=(81)
b^2=(81/20.25) or 4
square root both sides
b=2
6 0
3 years ago
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

5 0
2 years ago
Five twelfths ot the participants at a conference brought laptop computers with them
elena-14-01-66 [18.8K]

The number of participants with laptop is 115 and without laptop is 161

<u>Step-by-step explanation:</u>

Total number of participants= 276

Participants with laptop = (5/12) 276

= 115

Participants without laptop= 276 - 115

= 161

5 0
3 years ago
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