Please help. Don’t understand this math problem. I’ll mark you as brainliest if correct!

Mathematics

1 answer:

Tanya [424]3 years ago

3 0

Answer:

I believe it is B

Step-by-step explanation:

plug in 4 where t is

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How to turn 1/4 ÷9\10 into a mixed fraction?

elena-14-01-66 [18.8K]

Divide: 1
4
: 9
10
= 1
4
· 10
9
= 1 · 10
4 · 9
= 10
36
= 5
18

To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.

5 0

3 years ago

Help me please!!!!!!!!

Vedmedyk [2.9K]

48 ÷ 200 = 0.24

0.24 × 25 = 6

She will pay $6

4 0

3 years ago

Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$