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Andrej [43]
3 years ago
10

Math help 100 points ALSO CHECK OUT MY PROFILE (MANY UNANSWERED QUESTIONS)!!!!!

Mathematics
2 answers:
amm18123 years ago
5 0
Midpoint formula:
1. Point 1 (-2,2) Point 2 (4,-1)
Midpoint: (-2+4/2, 2-1/2)(2/2, 1/2)(1, 1/2)
2. Point 1 (-3,-5)Point 2 (2, 5)
Midpoint: (-3+2/2, -5+5/2)(-1/2, 0)
Distance between two points formula:

1. Point 1 (-2, 2)Point 2 (4, -1)





2. Point 1 (1, 2)Point 2 (4, 7)





Studentka2010 [4]3 years ago
3 0
Midpoint formula:
( \frac{x1 + x2}{2}   \:  \frac{y1 + y2}{2} )
1. Point 1 (-2,2)
Point 2 (4,-1)

Midpoint: (-2+4/2, 2-1/2)
(2/2, 1/2)
(1, 1/2)

2. Point 1 (-3,-5)
Point 2 (2, 5)

Midpoint: (-3+2/2, -5+5/2)
(-1/2, 0)

Distance between two points formula:

\sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2}  }
1. Point 1 (-2, 2)
Point 2 (4, -1)

\sqrt{(4 + 2) {}^{2}  + ( - 1 - 2) {}^{2} }
\sqrt{6 {}^{2} + ( - 3) {}^{2}  }
\sqrt{36 + 9}
\sqrt{45}
6.7
2. Point 1 (1, 2)
Point 2 (4, 7)

\sqrt{(4 - 1) {}^{2} + (7 - 2) {}^{2}  }
\sqrt{3 {}^{2} + 5 {}^{2}  }
\sqrt{9 + 25}
\sqrt{34}
5.8
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a

Step-by-step explanation:

I think that right so let me know if It is right

7 0
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Lina20 [59]
The answer is y = -1/3x + 2

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The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

So, the probability that a switch fails in the first year is

\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
3 years ago
I really need help fast
fiasKO [112]

Answer:

x=2

Step-by-step explanation:

Since rectangles have 90* angles at each corner, we can say the two equations in the corner equal to 90*

so,

13x+34+10x+10=90

23x+44=90

23x=46

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3 years ago
Convert 86 to base 5.<br>​
dimulka [17.4K]

Answer:

321

Step-by-step explanation:

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