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saveliy_v [14]
3 years ago
14

Let ​f(x)=x^2 and ​g(x)=x-3. Find ​(f​ º g)(​-1).

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0

Answer:

Step-by-step explanation:

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Twenty six equals eight plus v
Mumz [18]

18. You can do this in a calculator. 26 - 8 = 18. v = 18.

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What is the end behavior of the graph of the polynomial function f(x) = –x5 + 9x4 – 18x3?
Oksanka [162]

Answer:

As x approaches ∞, y approaches -∞

As x approaches -∞, y approaches ∞

Step-by-step explanation:

f(x) = -x^5 + 9x^4 - 18x^3

F(x) is a fifth degree (odd function ) with negative leading coefficient

If exponent is odd and leading coefficient is negative then end behavior is

As x approaches ∞, y approaches -∞

As you go on the right , f(x) goes down

As x approaches -∞, y approaches ∞

As you go on the left , f(x) goes up

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Which statement is not correct?
Pachacha [2.7K]

Answer:

b.) because it is over 90*

Step-by-step explanation:

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2 years ago
A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the
leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em />I \to<em> I-Beam</em>

<em />d_I \to<em> distance between I beam and the bridge</em>

<em />b \to<em> distance between each I beam</em>

<em />

Given that:

I = \frac 34 ft\\

d_I = 3 ft

<em />Length = 55ft\ 6in<em> --- length of the  bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

L_1 = 6 \times I

L_1 = 6 \times \frac 34

L_1 = \frac {18}4

L_1 = 4.5ft

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

d_1 =2 \times d_I

d_1 =2 \times 3ft

d_1 =6ft

There are 5 spaces between the I-beams

So, the length of the total spaces is:

L_2 = 5 \times b

L_2 = 5b

The total length is:

Length = L_1 + d_1 + L_2

So, we have:

4.5ft + 6ft + 5b = 55ft\ 6in

Collect like terms

5b = 55ft\ 6in - 4.5ft - 6ft

5b = 44.5ft\ 6in

Convert inches to feet

5b = 44.5ft\ + \frac{6}{12}ft

5b = 44.5ft\ + 0.5ft

5b = 45ft

Divide both sides by 5

b = 9ft

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

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2 years ago
If 5(2x - 1) = 35, then x =​
SIZIF [17.4K]

Answer:

x = 4

Step-by-step explanation:

Given

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x = 4

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