Answer: The velocity of the vehicle at 0 s is 0 m/s
Explanation:
The Velocity vs. Time graph of this situation is shown in the attached image. As we can see, we have five segments:
1) When the vehicle accelerates from 0 to 30 m/s in 10 seconds, which means at 0 seconds the vehicle's velocity was 0 m/s. In addition, as the vehicle goes from zero to a positive velocity, we have a positive slope.
2) Then the vehicle travels for 15 seconds at a constant velocity, that is why we do not have a slope in this section, since the vehicle kept its 30 m/s.
3) The vehicle comes to a stop in the next 5 seconds, that is why we observe an abrupt change in the graph and a negative slope.
4) The car waits 10 seconds in that stop, again we have a line with no slope
5) Finally, the car accelerates from 0 to -10 m/s in the next 5 seconds. This means the car changed its direction.
Answer:
10.6
Step-by-step explanation:
1. First, we need to find which digits √(113) is between, and that would be 10 and 11.
2. Okay, so √(113) is between 10 and 11, meaning 113 is between 100 and 121.
3. Since 113 is a little over half between 100 and 121, let's multiply 10.6 by 10.6 to see how close we are to 113:
4. 112.36 is pretty close to 113, therefore, the dot on the number-line should be placed at 10.6.
Given:
(2, 4) and (3, 3) are on the line.
To find:
The equation of line in point slope form.
Solution:
If a line passes through a point with slope m, then the point slope form of the line is
(2, 4) and (3, 3) are on the line. So, slope of the line is
The slope of a line is -1 and it passes through (2,4). So, an equation in point slope form is
Therefore, an equation of the line in point slope form is .