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Cloud [144]
3 years ago
12

PLEASE HELP WILL MARK BRAINLIEST THANK YOU

Mathematics
1 answer:
ahrayia [7]3 years ago
7 0

Answer:

You  \: draw  \: a \:  picture  \:  which \\  represent \:  your  \: problem. \\Since \:  R  \: is \:  on \:  the  \\  segment  \: QS,  \: the  \: length \:  of \\  QS \:  is \:  equal \:  to \:  length  \\  of \:  QR  \: plus  \: length \:  of \:  RS \\ QS=QR+RS \\ 2x+2=3x-5+5x-5 \\Solve \:  for \:  x \\ 2x+2=8x \\ 6x=2 \\x=2/6=1/3 \\ Now,  \: use \:  value  \\  of  \: x \:  to  \: calculate \:  QR

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The pass mark for an exam is 92% <br> abbi scored 62 out of 68 <br> does she pass the exam
BartSMP [9]

Answer:

68/100*92= 62.56

No abbi does not pass exam.

7 0
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denis23 [38]

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C

Step-by-step explanation:

8 0
3 years ago
PLEASE HELO ASAP WILL MARK BRAINLIEST
ss7ja [257]
A.) 1/2

B.) 3

For the first one, just plug the value of x (4) everywhere you see x in the formula.

For the second one, place 1 wherever you see f(x)

Hope this helps
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3 years ago
Which undefined terms are needed to define parallel lines
skelet666 [1.2K]
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3 years ago
10) Show that in a group of 10 people (where any two people are either friends or enemies), there are either three mutual friend
ddd [48]

Answer with explanation:

Number of People in the group =10 People

The combination between two people is that, they can be either friends or enemies.

Total number of Possible Relation

                            =18 +16+14+12+10+8+6+4+2

                            = 90 Relations in all.

Out of 90 relations , 45 will be friends and 45 will be enemies.

⇒Now, we have to prove that, between 10 people, there are either three mutual friends or four mutual enemies, and there are either three mutual enemies or four mutual friends.

→→If there are three mutual friends, total number of people in the group =3 ×2=6 people in the group

And, four mutual enemies in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual friends or four mutual enemies

   =6 +4

   =10

Hence proved.

→→→→Second part is ,in this group there can be either three mutual enemies or four mutual friends.

⇒If there are three mutual enemies, total number of people in the group =3 ×2=6 people in the group

And, four mutual friends in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual enemies or four mutual enemies

   =6 +4

   =10

Hence proved.

3 0
3 years ago
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