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2 years ago

What is √34cos(x-46.7) =4

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

5 0

Answer:

x = 93.4° ( to 1 dec. place )

Step-by-step explanation:

Given

$\sqrt{34}$ cos(x - 46.7)° = 4 ( divide both sides by $\sqrt{34}$ )

cos(x - 46.7)° = $\frac{4}{\sqrt{34} }$ , thus

x - 46.7 = $cos^{-1}$ ( $\frac{4}{\sqrt{34} }$ ) ≈ 46.7° ( add 46.7° to both sides )

x ≈ 93.4°

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Solve x for 3х – 1 = - 13

ddd [48]

Step-by-step explanation:

3x=-13+1

3x = - 12

x = -12/3

x= -4

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2 years ago

Read 2 more answers

Drag each tile to the correct box.

Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

$a=3$

$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

$g(x)=\frac{1}{5}(4)^x$

$f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}$

$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0

3 years ago

Jordan wants to measure a length of fabric, but the only tape measure she has is damaged. The first number on her tape measure i

Alex

Djdjxkdjdkdkdjddjdjdj yuppppppppp 37387(5y6666+4)WEI

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2 years ago

Two sides of an acute triangle meaure 5 inches and 8 inches. The length of the longest side is unknown. What is the greatest pos

gladu [14]

The greatest whole possible whole number length of the unknown side is 9 inches.

<h3>How to identify if a triangle is acute?</h3>

Let us have:

H = biggest side of the triangle

And let we get A and B as rest of the two sides.

Then we get:

$A^2 + B^2 < C^2$

then the triangle is acute

Two sides of an acute triangle measure as 5 inches and 8 inches

The length of the longest side is unknown.

We have to find the length of the unknown side

WE know that the longest side of any triangle is a hypotenuse

For an acute triangle we know:

$A^2 + B^2 < C^2$

Here in this sum,

a = 5 inches

b = 8 inches

c = ?

Substituting we get,

$A^2 + B^2 < C^2\\\\5^2 + 8^2 < C^2\\\\25 + 64= C^2$

c < 9

Hence, The greatest whole possible whole number length of the unknown side is 9 inches.

Learn more about angles;

brainly.com/question/14489478

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anyanavicka [17]

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The candy bar was marked down 30%.
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3 years ago