I. Multiply the first function by the second one.
f(x)*g(x) = (x^2+3x-4)*(x+4) = x^3 + 3x^2 - 4x + 4x^2 + 12x -16 = x^3 +7x^2 + 8x - 16.
The domain of this new function is the set of all real numbers (R). Other notation: from minus infinity to plus infinity. We came to this conclusion because the new function poses no restrictions; regardless of which x-value you take, you will get the appropriate y-value.
II. f(x)/g(x) = (x^2+3x-4)/(x+4) =
Ask yourself: which two numbers add up to 3 and multiply to -4? It's -1 and 4. Now we can represent f(x) as (x-1)(x+4).
Since we're dividing these 2 brackets by g(x)=x+4, we may now cancel (x+4). All that's left is x-1.
The domain here is the same as in the previous task - it is R.
The root of an equation f(x) is the x value(s) for which f(x) = 0.
So, if you have f(x) = 6x + 3, to find its root(s), you do 0 = 6x + 3, and then
0 - 3 = 6x + 3 - 3
-3 = 6x + 0
-3 = 6x
-3/6 = 6x/6
-1/2 = x
x = -1/2 is the one and only root (Linear functions will always have 0 or 1 root. They will have zero roots if they are horizontal lines of the form y = c, where c is any constant, and they will have one root if they are of the form y = mx + b, where m is not 0.)
Answer:b) 0.44
Step-by-step explanation:
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Answer:
what?
Step-by-step explanation:
