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LenKa [72]
4 years ago
5

Find dy/dx y= ln (x/1+x²) thank you!

Mathematics
1 answer:
tekilochka [14]4 years ago
4 0
<span>y = ln(x/(1+x²))

</span>y = ln(x) - ln(1+x²)

dy/dx=  ln[(1/x)] - ln[((2x)/(1+x²))]
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Our first step is to subtract 4 from both sides.

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To check your work, simply plug in the value of x into x in the original equation.

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