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4 years ago

5

Find dy/dx y= ln (x/1+x²) thank you!

1 answer:

tekilochka [14]4 years ago

4 0

<span>y = ln(x/(1+x²))

</span>y = ln(x) - ln(1+x²)

dy/dx= ln[(1/x)] - ln[((2x)/(1+x²))]

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