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mylen [45]
3 years ago
14

X sqaured plus 4x plus 20 equlas 12x minus 5

Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

Answer:

No real roots/solutions

Step-by-step explanation:

x² + 4x + 20 = 12x - 5

x² - 8x + 25 = 0

Using quadratic formula:

b² - 4ac = (-8)² - 4(1)(25) = -36

Since sqrt(-36) is not a real no.,

This equation has no real roots

skelet666 [1.2K]3 years ago
3 0

Answer:

x² + 4x + 20 = 12x - 5

x² + 4x - 12x + 20 + 5 = 0

x² - 8x + 25 = 0

Δ = √b² - 4ac

= √(-8)² - 4×1×25

= √64-100

= √(-36)

x ∉ R

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deff fn [24]
The answer would be x^2-18x+81. This can be found be writing "(x-9)^2" twice, and distributing. Combine like terms, and you should get this answer.
6 0
3 years ago
6x – 4y = -5<br>4x + 5y = -11​
kipiarov [429]

Answer:

x= -1.5, y= -1

Step-by-step explanation:

6x= -5+4y

x= (-5+4y) / 6

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4(-5+4y) + 5*6y = -11*6

-20+16y+30y= -66

16y + 30y = -66+20 = -46

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y= -46 / (16 + 30)

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3 years ago
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8 0
3 years ago
How many solutions does 2x+2-3x=3x-4
DerKrebs [107]

Answer:

1 solution (x = 1.5)

Step-by-step explanation:

2x + 2 - 3x = 3x - 4

First, combine like terms

2 - x = 3x - 4

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Add x to both sides

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Divide both sides by 4

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4 0
2 years ago
Read 2 more answers
A bag has 4 yellow, 6 red, 2 green, and 8 purple marbles. What is the probability of picking a purple marble, not replacing it,
Dominik [7]

Answer:

The probability of picking two consecutive purple marbles without replacement is 14.72%.

Step-by-step explanation:

Initially, there are 4+6+2+8 = 20 total marbles.

The probability of picking a purble marble is

P_{1} = \frac{number of purple marbles}{number of total marbles}

P_{1}= \frac{8}{20} = 0.4

Since there are no replacements, there are now 19 total marbles, 7 of which are purple. So, the probability of picking another purple marble is

P_{2} = \frac{7}{19} = 0.368

The probability P of picking a purble marble(P_{1}), not replacing it, and then picking another purple marble(P_{2}) is:

P = P_{1}*P_{2} = 0.4*0.368  = 0.1472 = 14.72%

8 0
3 years ago
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