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mylen [45]
3 years ago
14

X sqaured plus 4x plus 20 equlas 12x minus 5

Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

Answer:

No real roots/solutions

Step-by-step explanation:

x² + 4x + 20 = 12x - 5

x² - 8x + 25 = 0

Using quadratic formula:

b² - 4ac = (-8)² - 4(1)(25) = -36

Since sqrt(-36) is not a real no.,

This equation has no real roots

skelet666 [1.2K]3 years ago
3 0

Answer:

x² + 4x + 20 = 12x - 5

x² + 4x - 12x + 20 + 5 = 0

x² - 8x + 25 = 0

Δ = √b² - 4ac

= √(-8)² - 4×1×25

= √64-100

= √(-36)

x ∉ R

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Help me plz!
Goryan [66]

Answer:

1,451.61 cm²

Step-by-step explanation:

A = LW

A = 38.1 x 38.1 (since a checkerboard has to be square)

A = 1,451.61

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3 years ago
Jasmine needs to make a bouquet of 24 yellow and orange carnations. The ratio of yellow carnations to all of the
Ghella [55]

Answer:

I'm not sure what the answer is

4 0
3 years ago
In a NiCd battery, a fully charged cell is composed of Nickelic Hydroxide. Nickel is an element that has multiple oxidation stat
Westkost [7]

Answer:

P(cell has at least one of the positive nickel-charged options) = 0.83.

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.

Step-by-step explanation:

It is given that the Nickel Charge Proportions found  in the battery are:

0 ==> 0.17

.

+2 ==> 0.35

.

+3 ==> 0.33

.

+4 ==> 0.15.

The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.

a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.

Or:

P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.

b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)

= 1 -  P(a cell has +4 nickel-charged options)  '.' because +4 is only positive nickel charge greater than +3      

= 1 - 0.15

=  0.85

To summarize:

P(cell has at least one of the positive nickel-charged options) = 0.83!!!

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!

8 0
3 years ago
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Answer:

\boxed{\boxed{\sf x=-6}}

Step-by-step explanation:

\sf \cfrac{9-x}{5}=3

\sf \cfrac{5\left(9-x\right)}{5}=3\times \:5

\sf 9-x=15

\sf 9-x-9=15-9

\sf -x=6

\sf \cfrac{-x}{-1}=\cfrac{6}{-1}

\sf x=-6

<h3>⚝──⭒─⭑─⭒──⚝⚝──⭒─⭑─⭒──⚝</h3>
4 0
3 years ago
How would we solve 6/15=2/c
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The answer is c=5 hope this helps
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