Question

X sqaured plus 4x plus 20 equlas 12x minus 5

Answer 1

Answer:

No real roots/solutions

Step-by-step explanation:

x² + 4x + 20 = 12x - 5

x² - 8x + 25 = 0

Using quadratic formula:

b² - 4ac = (-8)² - 4(1)(25) = -36

Since sqrt(-36) is not a real no.,

This equation has no real roots

Answer 2

Answer:

x² + 4x + 20 = 12x - 5

x² + 4x - 12x + 20 + 5 = 0

x² - 8x + 25 = 0

Δ = √b² - 4ac

= √(-8)² - 4×1×25

= √64-100

= √(-36)

x ∉ R