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Vladimir79 [104]
3 years ago
7

Write an expression for the most apparent nth term of the sequence (Assume that n begins with 1) 1,4,7,10,13

Mathematics
1 answer:
kobusy [5.1K]3 years ago
8 0
 The answer is <span>2n * (-1)^(n + 1)

</span><span>The numerator seems to be accelerated via 7 each and every time, so if it starts with the 1st term being one, it incredibly is secure to declare the nth numerator is 7^(n-a million) Likewise, the backside has a million, a million*2, a million*2*3, a million*2*3*4, and a million*2*3*4*5. This seems to be factorials, so we are in a place to declare the nth term interior the denominator is n! putting those mutually, the nth term is 7^(n-a million)/n!
</span>I hope this helped God Bless!
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lozanna [386]

Answer:

B. -x + 8

Step-by-step explanation:

Given expression

\dfrac{8-4(x-6)}{4}

Consider the numerator 8-4(x-6).

First, use distributive property:

8-4(x-6)=8-(4x-24)

Open the brackets:

8-(4x-24)=8-4x+24

Combine the like terms:

8-4x+24=(8+24)-4x=32-4x

Again use distributive property:

32-4x=4\cdot 8-4x=4(8-x)

Now, the expression is

\dfrac{4(8-x)}{4}=8-x\ \text{or}\ -x+8

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

I can upload a couple of answers at a time, I will just have to keep editing it lol

1) SSS

2) SSS

3) m<t=m<r

4) DC=NB

5) yes SAS

6) yes SSS

7) yes HA

8) yes HA

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I have to go somewhere now but I can finish when I get home (if you are still taking the test)

You got this!

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